MATHEMATICS PROBLEM SOLVER

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Thursday, 7 September 2017

LOGARITHMS 3

If Log₃(x²+7x+7)=0; find x.

Solution

Log₃(x²+7x+7)=0

(x²+7x+7)=3⁰

x²+7x+7=1 [ Since n⁰=1 ]

x²+7x+7-1=0

x²+7x+6=0

We solve it by factorization;

x²+7x+6=0

x²+6x + x+6=0

x(x+6) + 1(x+6)=0

(x+6)(x+1)=0

x+6=0 OR x+1=0

x= -6 OR x= -1 answer

TRY THIS………………….

If Log₇(x²+ 17x + 101)=2; find x.

MATHEMATICS PROBLEM SOLVER

Thursday, 7 September 2017

LOGARITHMS 3

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