If F(x) = log2x,
Find F(1/ 8192)
Solution
F(x) = log2x
F(1/8192) = log2(1/ 8192)
F(1/8192) = log2 8192-1
F(1/8192) = log2(213)-1
F(1/8192) = log22(13 x -1)
F(1/8192) = log22-13
F(1/8192) = -13log22
F(1/8192) = -13 x 1
F(1/8192) = -13
Therefore F(1/ 8192) =
-13
TRY THIS…………………
If F(x) = log5x,
Find F(1/3125)
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