Thursday, 10 August 2017

FUNCTIONS 2


If F(x) = log2x, Find F(1/ 8192)

Solution

F(x) = log2x

F(1/8192) = log2(1/ 8192)

F(1/8192) = log2 8192-1

F(1/8192) = log2(213)-1

F(1/8192) = log22(13 x -1)

F(1/8192) = log22-13

F(1/8192) = -13log22

F(1/8192) = -13 x 1

F(1/8192) = -13

Therefore F(1/ 8192) = -13


TRY THIS…………………


If F(x) = log5x, Find F(1/3125)

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