A settlement has a
population of 2000 people. Each year 12%of the people leave the settlement. How
many people will remain after 3 years?
solution
f(t) = A ( 1 -12/100)t
= 2000(1 – 0.12)t
= 2000 x (0.88)3
= 2000 x 0.88x 0.88x 0.88
= 2000 x 0.681472
= 1362.944 (1363
approximate)
Therefore there will be 1363 people remaining after three
years of decay
TRY THIS………….
A settlement has a
population of 5000 people. Each year 5%of the people leave the settlement. How
many people will remain after 4 years?