The sum of five consecutive numbers
is 475. Find the 3rd number.
Solution
Let the numbers be as shown in the table
below
1st
number
|
2nd
number
|
3rd
number
|
4th
number
|
5th
number
|
TOTAL
|
n
|
n+1
|
n+2
|
n+3
|
n+4
|
475
|
Then, n + (n+1) + (n+2) + (n+3)+
(n+4) = 475
5n + 1+2+3 +4= 475
5n + 10= 475
5n = 475 -10
5n = 465
5n
= 465
5
5
n = 93
3rd number = n + 2
=
93 + 2
=
95
Hence the 3rd number is 95
TRY
THIS..................
The sum of five consecutive numbers
is 510. Find the 3rd number.
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