In
Civics test the following marks were recorded.
marks
|
10-19
|
20-29
|
30-39
|
40-49
|
50-59
|
60-69
|
70-79
|
No. of students
|
4
|
5
|
7
|
9
|
6
|
5
|
4
|
Calculate
the mean.
Solution
In
this question we are going to apply the method of assumed mean.
Here
you are required to produce the frequency distribution table.
Let
us take 54.5 as our assumed mean (A). Take away the assumed mean from each
class mark.
Class interval
|
Class mark (x)
|
d=x-A
|
Frequency(f)
|
fx
|
fd
|
10-19
|
14.5
|
-40
|
4
|
58
|
-160
|
20-29
|
24.5
|
-30
|
5
|
122.5
|
-150
|
30-39
|
34.5
|
-20
|
7
|
241.5
|
-140
|
40-49
|
44.5
|
-10
|
9
|
400.5
|
-90
|
50-59
|
54.5
|
0
|
6
|
327
|
0
|
60-69
|
64.5
|
10
|
5
|
322.5
|
50
|
70-79
|
74.5
|
20
|
4
|
298
|
80
|
|
∑f = 40
|
∑fx = 1770
|
∑fd = -410
|
Mean = A + ∑fd
∑f
Mean = 54.5 + -410
40
Mean = 54.5 + (-10.25)
Mean = 44.25
Hence Mean = 44.25
TRY
THIS………..
In Civics test the following marks were recorded.
marks
|
10-14
|
15-19
|
20-24
|
25-29
|
30-34
|
35-39
|
40-44
|
No. of students
|
4
|
5
|
7
|
9
|
6
|
5
|
4
|
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