It is a site for parents, students and teachers. This site can help O-LEVEL or GCSE secondary school students in mastering mathematics subject. It intends to involve the learners by making them follow up the examples before they can do questions on their own at the TRY THIS.... section. There are some videos, tests, quizzes and past examination questions. Learning the examples will ultimately give students the required confidence in solving various questions in mathematics.
Thursday, 21 August 2025
VECTORS J5
If
u = 60i + 2j and v = 3i + 10j find
7u - 3v
solution
=
7u - 3v
=
7(60i + 2j) - 3(3i + 10j)
=
420i + 14j - 9i - 30j
=
(420i - 9i) + (14j - 30j)
=
411i - 66j
Hence 7u - 3v = 411i -
66j
TRY
THIS..................
If
u = 9i + 3j and v = 2i + 6j;
find 8u - 4v.
LOGARITHMS J7
Evaluate Log2(1/256
÷ 8).
Solution
= Log2(1/256
÷ 8)
= Log2(1/256)
- Log28
(applying the quotient rule)
= Log2256-1 -
Log223 (
256= 28 and 8=23 )
= -1Log228
- 3Log22 ( remember
Logaac = cLogaa )
= -1 x 8Log22
- 3Log22
= (-8 x 1) - (3 x
1) ( remember Logaa =
1 )
= -8 - 3
= -11
Hence Log2(1/256 ÷ 8)
= -11
TRY THIS...............
Evaluate Log2(1/1024
÷ 32).
LOGARITHMS J6
Find
x if Logx128 = 7
solution
Logx128
= 7
128
= x7 .
27 =
x7 . [since 625 = 54 by prime factorization]
27 =
x7 . [ powers ARE SAME, they cancel out]
x
= 2
Hence
x = 2
TRY
THIS..................
Find
y if Logy64 = 3
FACTORIZE J6
Factorize 1-121B2
Solution
We use difference of
two squares a2 – b2 = (a - b)(a + b)
1-121B2 =
12-121B2
= 12-112B2
= 12-(11B)2
=
(1 - 11B)(1 + 11B)
Hence 1 - 121B2 =
(1 - 11B)(1 + 11B)
TRY THIS…………….
Factorize 16 – 4C2
EXPONENTIALS J3
If a2 =
7; find the value of a6.
solution
a6 =
(a2)3.
a6 = (7)3.
[ since a2 = 30]
a6 = 7
x 7 x 7
a6 =
343 answer
TRY
THIS.........................
NECTA FORM II - 2012
QN. 8
If a2 =
12; find the value of a4.
Wednesday, 20 August 2025
PERCENTS J4
In a box of 500 books,
60 are red in colour, 140 are yellow in colour while the rest are bluish in
color. Give out the percentage of blue books.
solution
1st we have to get the
number of blue books.
blue books = 500
– 60 - 140 = 300
then,= 300 x
100
500
then,= 300
5
= 60%
Hence
percentage of blue books is 60%
TRY
THIS...............
In a box of 800 books,
300 are yellow in colour, 200 are red, while the rest are greyishish in color.
Give out the percentage of grey books.
SQUARES J2
Evaluate 203962 –
203862
Solution
We use difference of two squares;
a2 – b2 =
(a – b)(a + b)
203962 –
203862 = (20396 + 20386)(20396 – 20386)
= (40782)(10)
= 407820
203962 –
203862 = 407820
TRY THIS…………….
Evaluate 4573082 –
4572082
FUNCTIONS J2
Find the axis of
symmetry for F(x) = 4x2 + 20x + 8
Solution
a=4, b=10
Axis of symmetry
= -b/2a
= -(20)
2 x 4
= -20
8
Hence the axis of
symmetry is -2.5
TRY THIS…………………
Find the axis of
symmetry for F(x) = 6x2 + 40x + 3
ALGEBRA J3
Solve the following equations by substitution method.
x + y = 3
x + 3y = -3
Solution
x + y = 3 ----------- (i)
x + 3y = -3 ---------- (ii)
from equation (i)
x + y = 3
x = 3 - y ----------(iii)
substitute equation (iii) in (ii) above,
x + 3y = -3
(3 - y) + 3y = -3
3 - y + 3y = -3
3 + 2y = -3
2y = -3 - 3
2y = -6
[since –y+3y=2y]
2y = -6
2 2
y = -3
From equation (iii)
x = 3 - y
x = 3 – (-3) ----------(iii)
x = 3+3
x=6
Hence x=6 and y=-3.
TRY
THIS………………………..
5x - 2y = 14
x - y = 4
EXPAND J2
Expand 7w(w – 60 - w2)
solution
= 8w(w – 60 - w2)
= (8w x w) – (8w x 60)
+ (8w x w2)
= 8w2 –
480w + 8w3 answer
TRY THIS………..
Expand 4e(e + 70 – e2)
Wednesday, 30 July 2025
ALGEBRA J1
Expand 8w(w – 3 + w2)
solution
= 8w(w – 3 + w2)
= (8w x w) – (8w x 3)
+ (8w x w2)
= 8w2 –
24w + 8w3 answer
TRY THIS………..
Expand 10p(p + 7 – p2)
LOGARITHMS J1
If Logax =
46, find Loga(1/x5)
Solution
= Loga(1/x5)
= Logax-5
= -5 x Logax [Since Logaxn = nLogax]
= -5 x 46
= -230
TRY THIS………..
If LogaW= 60,
find Loga(1/W7)