Tuesday, 11 July 2023

LOGARITHMS K2

 

Evaluate Log100000 +  log 0.00001 + log3243

 

Solution

 

= Log100000 +  log 0.001 + log3243

 

= Log105 +  log 10-3 + log335

 

= 5Log10 +  (-3log 10) + (5log33)    [since logaa= nlogaa]

 

= (5x1) + (-3x1) + (5x1)             [since logaa = 1]

 

= 5 + (-3) + (5)

 

= 7

 

Hence Log100,000 +  log 0.001 + log3243 = 7

 

TRY THIS...............................

 

Evaluate Log10,000,000 +  log 0.01 + log3729

 


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