Find the
maximum value of the quadratic equation:7-6t-8t2.
Solution
a=-8, b=-6,
c=7
Maximum = 4ac-b2
4a
Maximum = (4
x -8 x 7) - (-6)2
4(-8)
Maximum = (-224)-
36
32
Maximum= -260 since (-224)- 36= -260
32
Maximum = -130
= -65
16
8
Hence maximum value is -65/8
TRY THIS………………………………..
NECTA
2003 QN. 10c
Find the
maximum value of the quadratic equation:3+30t-5t2.
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