Find
the maximum value of the quadratic equation:3-6t-8t2.
Solution
a=-8,
b=-6, c=3
Maximum
= 4ac-b2
4a
Maximum
= (4 x -8 x 3) - (-6)2
4(-8)
Maximum
= (-96)- 36
32
Maximum=
-132 since
(-96)- 36=-132
32
Maximum
= -66 = -33
16 8
Hence maximum value is -33/8
TRY
THIS………………………………..
NECTA 2003 QN. 10c
Find
the maximum value of the quadratic equation:3+30t-5t2.
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