Friday, 4 May 2018

SETS 2


If n(AnB)=45, n(B)= 96 and n(AuB)= 146, find n(A)

Solution

n(AuB) = n(A) + n(B) - n(AnB)

146 = n(A)  + 96 - 45

146 = n(A)  +  51

146 - 51 = n(A) 

95 = n(A) 

Hence n(A)  = 95 answer


TRY THIS………….



If n(AnB)=44, n(B)= 97 and n(AuB)= 145, find n(A)


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