A bag contains 12 red balls
and 8 blue balls. Two balls are taken from the bag. What is the probability
that they are both red?
Solution
(This is a problem with
replacement)
n(R) = 12, n(B) = 8, n(S) = 20
P(R) = n(R)
n(S)
1st pick = 12/20
2nd pick = 12/20 as well.
P(RR) = 12
x 12
20 20
P(RR) = 9
25
Therefore Probability
of drawing a red ball is 16/81
TRY THIS
..............
A bag contains 8 purple
stones and 14 blue stones. Two stones are taken from the bag. What is the
probability that they are both blue?
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