Find
the maximum value of the quadratic equation:5-3t-8t2.
Solution
a=-8,
b=-3, c=5
Maximum
= 4ac-b2
4a
Maximum
= (4 x -8 x 5) - (-3)2
4(-8)
Maximum
= (-160)- 9
-32
Maximum=
-169 since
(-160)- 9= -169
-32
Maximum
= 169
32
Hence maximum value is 169/32
TRY
THIS………………………………..
Find
the maximum value of the quadratic equation:6+10t-4t2.
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