A number is chosen at random from 21
– 32 inclusive. Find the probability that it is a prime or a multiple of 3.
Solution
THIS
IS A MUTUALLY EXCLUSIVE EVENT
Let n(S) represent sample space
P(M) = probability of a multiple of 3
P(R) = probability of prime number
n(S) = {21, 22, 23, 24, 25, 26, 27,
28, 29, 30, 31, 32} = 12
n(M) = {21, 24, 27, 30} = 4
n(R) = {23, 29, 31} = 3
P(M) = 4/12
P(R) = 3/12
………………………….
P(MuR) = P(M) + P(R)
P(MuR) = 4/12 + 3/12
= 7/12
= 7/12
P(MuR) = 7/12 answer
TRY THIS…………………
A number is chosen at random from 17
– 30 inclusive. Find the probability that it is a prime number or a multiple of
4.
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