MATHEMATICS PROBLEM SOLVER

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Monday, 4 July 2016

LOGARITHMS 6

Evaluate Log1000 + log0.00001 + log₃243

Solution

= Log1000 + log0.00001 + log₃243

= Log10³ + log10^-5 + log₃3^-5

= 3Log10 + (-5log10) + (-5log₃3) [since log_aaⁿ= nlog_aa]

= (3x1) + (-5x1) + (-5x1) [since log_aa = 1]

= 3 + (-5) + (-5)

= 3 - 10

= -7

Hence Log1000 + log0.00001 + log₃243 = -5

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Evaluate Log100,000 + log0.01 + log₃729

MATHEMATICS PROBLEM SOLVER

Monday, 4 July 2016

LOGARITHMS 6

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