Sunday, 23 November 2014

EXPONENTIALS-1




If (x3)(y2) = 500; find x and y.

solution

(x3)(y2) = 500  [500=2x2x5x5x5 by prime factorization].

(x3)(y2) = (53 )x (22)     [ since 500=53 x 23].

equating equal powers,

(x3) = (53)   

x   =   5

also,

(y2) = (22)

 y    =   2

x   =   5 and y    =   2

TRY THIS…………

If (m3)(n5) = 4000; find m and n.

No comments:

Post a Comment