Wednesday, 22 February 2017

ALGEBRA 1N







TRIGONOMETRY 1A


Given that Sin Ө  = 1/9, Find Cos Ө.

Solution

Sin2Ө + Cos2Ө = 1

(1/9)2 + Cos2Ө = 1

Cos2Ө = 1 - (1/9)2

Cos2Ө = 1 - 1/81

Cos2Ө =81/81 - 1/81

Cos2Ө = 80/81

Cos2Ө = (80/81)       keeping under radical sign both sides

CosӨ =  (80/81)

CosӨ =  80      since √81=9
                9

CosӨ =  (2x2x2x5)     
                9

CosӨ =  2(10)     
                9

CosӨ =  210      answer
                 9
  
TRY THIS………


Given that Sin Ө  = 1/5, Find Cos Ө. 

FACTORIZE 1C

Factorize 3x2 + 8x - 16.

Solution

= 3x2 + 8x - 16. We split the middle term (8x) to be (12x - 4x).

= 3x2 + 12x - 4x - 16

=  (3x2 + 12x) - (4x + 16) we group by using brackets.

= 3x(x + 4) - 4(x + 4).

= (3x - 4) (x + 4)

Hence 3x2 + 8x - 16= (3x - 4) (x + 4)answer.


TRY THIS…..


Factorize 3x2 - 13x - 16.

Friday, 17 February 2017

BODMAS 1A


Evaluate 50 x (45 – 37) ÷ (345-343)

Solution

We apply BODMAS.

= 50 x (45 – 37) ÷ (345-343)

= 50 x 8 ÷ (345-343) [After dealing with 1st brackets]

= 50 x 8 ÷ 2     [After dealing with 2nd brackets]

= 50 x  4     [After dividing]

= 200     [After multiplying]

Hence  50 x (45 – 37) ÷ (345-343) = 200

TRY THIS……………….


Evaluate 8 x (96 – 16) ÷ (83-43)

MATRIX 1P



UNITS OF DISTANCE 1B


Change 21260m into Km.

Solution

1Km = 1000m
?  =  21260m


= 1  x  21260
       1000

=     21260
       1000

= 21.26Km


TRY THIS...................................


Change 68042m into Km.

MATRIX 1N



SETS 1C


If n(A)= 60 , n(B)= 90 and n(AuB)= 130, find n(AnB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

130 = 60 + 90 - n(AnB)

130 = 150 - n(AnB)

130 - 150 = - n(AnB) [after transferring 150 on the left hand side]

-20 = -n(AnB)

n(AnB) = 20 [after dividing by -1 both sides]

Hence n(AnB) = 20 answer


TRY THIS………….



If n(A)= 74 , n(B)= 86 and n(AuB)= 125, find n(AnB).
==============================================

Thursday, 16 February 2017

MATRIX 1M


PERCENTAGE PROFIT 1A


A man got a profit of 7400/= after selling an item. Find the buying price if the percentage profit was 10%.

Solution

%’ge profit = Profit   X  100    [where B. P. represents Buying Price.]
                         B.P

10% = 7400   X  100   
            B.P.

B.P. x 10% = 740,000   x B.P.  [multiplying by B.P. both sides]
                       B.P.

B.P. x 10 = 740,000   

B.P. x 101 =   740,000   
  110                   10

B.P. =74,000
                      
Hence Buying Price was 74,000/=


TRY THIS………………


A man got a profit of 17,500/= after selling an item. Find the buying price if the percentage profit was 20%.