It is a site for parents, students and teachers. This site can help O-LEVEL or GCSE secondary school students in mastering mathematics subject. It intends to involve the learners by making them follow up the examples before they can do questions on their own at the TRY THIS.... section. There are some videos, tests, quizzes and past examination questions. Learning the examples will ultimately give students the required confidence in solving various questions in mathematics.
Wednesday, 22 February 2017
TRIGONOMETRY 1A
Given that Sin Ө = 1/9, Find Cos Ө.
Solution
Sin2Ө + Cos2Ө
= 1
(1/9)2 + Cos2Ө
= 1
Cos2Ө = 1 - (1/9)2
Cos2Ө = 1 - 1/81
Cos2Ө =81/81 -
1/81
Cos2Ө = 80/81
√Cos2Ө = √(80/81)
keeping under radical sign both sides
CosӨ = √(80/81)
CosӨ = √80 since √81=9
9
CosӨ = √(2x2x2x5)
9
CosӨ = 2√(10)
9
CosӨ
= 2√10 answer
9
TRY THIS………
Given that Sin Ө = 1/5, Find Cos Ө.
FACTORIZE 1C
Factorize 3x2 + 8x - 16.
Solution
= 3x2 + 8x - 16. We split the middle term (8x) to be (12x - 4x).
= 3x2 + 12x - 4x - 16
= (3x2 + 12x) - (4x
+ 16) we group by using brackets.
= 3x(x + 4) - 4(x + 4).
= (3x - 4) (x + 4)
Hence 3x2 + 8x
- 16= (3x - 4) (x + 4)answer.
TRY THIS…..
Factorize 3x2 - 13x - 16.
Friday, 17 February 2017
BODMAS 1A
Evaluate
50 x (45 – 37) ÷ (345-343)
Solution
We
apply BODMAS.
=
50 x (45 – 37) ÷ (345-343)
=
50 x 8 ÷ (345-343) [After dealing with 1st brackets]
=
50 x 8 ÷ 2 [After dealing with 2nd
brackets]
=
50 x 4 [After dividing]
=
200 [After multiplying]
Hence 50 x (45 – 37) ÷ (345-343) = 200
TRY
THIS……………….
Evaluate
8 x (96 – 16) ÷ (83-43)
UNITS OF DISTANCE 1B
Change
21260m into Km.
Solution
1Km
= 1000m
?
= 21260m
=
1 x 21260
1000
=
21260
1000
=
21.26Km
TRY THIS...................................
Change
68042m into Km.
SETS 1C
If n(A)= 60 , n(B)= 90 and n(AuB)= 130,
find n(AnB).
Solution
n(AuB) = n(A) + n(B) - n(AnB)
130 = 60 + 90 - n(AnB)
130 = 150 - n(AnB)
130 - 150 = - n(AnB) [after
transferring 150 on the left hand side]
-20 = -n(AnB)
n(AnB) = 20 [after dividing by -1 both
sides]
Hence n(AnB) = 20 answer
TRY THIS………….
If n(A)= 74 , n(B)= 86 and n(AuB)= 125,
find n(AnB).
==============================================
Thursday, 16 February 2017
PERCENTAGE PROFIT 1A
A man got a profit of 7400/=
after selling an item. Find the buying price if the percentage profit was 10%.
Solution
%’ge profit = Profit X
100 [where B. P. represents
Buying Price.]
B.P
10% = 7400 X
100
B.P.
B.P. x 10% = 740,000 x B.P. [multiplying by B.P. both sides]
B.P. x 10 = 740,000
B.P. x 101 = 740,000
110 10
B.P. =74,000
Hence Buying Price was 74,000/=
TRY THIS………………
A man got a profit of 17,500/=
after selling an item. Find the buying price if the percentage profit was 20%.
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