Find the midpoint of a line from (3, 12) to (5, 20)
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Thursday, 13 March 2025
GEOMETRY J3
BINARIES J1
p*q =(p-q)(6p+q) Find (2*-3)
solution
=(p-q)(6p+q)
=[2-(-3)][(6x2)+(-3)]
=[2+3][12+(-3)]
=(5)(9)
=45
Hence (2*-3) = 15
If p*q =(5p-q)(6p+q) Find (3*-4)
Friday, 18 October 2024
GP J1
The 1st term of a geometric
progression is 2 and the 5th term is 512. Find the common ratio.
Solution
G1=2, G5=512,
n=5
Gn = G1rn-1;
G5 = G1r5-1;
G5 = G1r4;
512 = 2 x r4;
512 = 2r4;
2
2
256 = r4; Finding the
fourth root of 256,
We do prime factorization of 256.
2 |
256 |
2 |
128 |
2 |
64 |
2 |
32 |
2 |
16 |
2 |
8 |
2 |
4 |
2 |
2 |
|
1 |
44 = r4; [equal
powers will cancel out]
4 = r
r = 4
Hence the common ratio is 4.
TRY THIS …………..
The 1st term of a geometric
progression is 3 and the 5th term is 9375. Find the common ratio.
GEOMETRY J3
The total interior angles of a regular polygon is 5,5800.
Find the interior angle.
Solution
(n-2)1800=
Total interior angles.
(n-2)1800 = 5,5800
(n-2)1800 = 5,5800
Dividing by 1800
both sides
1800 1800
(n-2) = 558279 After canceling by 2
1
18
9
(n-2) = 279 93 After canceling by 3
1
9 3
(n-2) = 93
31 After canceling by 3
again
1
3 1
(n-2)
= 31
n = 31+2
n = 33
i = (n-2)1800
n .
i = (33-2)1800
33
i = 31 x1800
33
i = 31 x 600
11
i = 1860/110
Interior angle=1860/110
TRY THIS……………….
The total interior angles of a regular polygon is 68400.
Find the interior angle.