SETS 1

If n(A)= 64 , n(B)= 96 and n(AuB)= 133, find n(AnB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

133 = 64 + 96 - n(AnB)

133 = 160 - n(AnB)

133 - 160 = - n(AnB) [after transferring 150 on the left hand side]

-27 = -n(AnB)

n(AnB) = 27 [after dividing by -1 both sides]

Hence n(AnB) = 27 answer

TRY THIS………….

If n(A)= 77 , n(B)= 88 and n(AuB)= 122, find n(AnB).