Saturday 9 December 2017

QUADRATICS 1


Given that one of the roots of the equation 5x2 + m(x+1) + 5 = 0 is 7, find m.

Solution

Substitute x=7, in the above equation.

5(7)2 + m(7+1) + 5 = 0
(5x49) + (m x 8) + 5 = 0
245 + 8m + 5 = 0
8m + 5 = -245
8m = -245 - 5
8m = -250
8m = -250
8         8
m=-125/8

Hence m=-125/8

TRY THIS…………………………..


Given that one of the roots of the equation 3x2 + e(x-2) + 3 = 0 is 4, find e.

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