FUNCTIONS 3

If F(x) = log₂x, Find F(32)

Solution

F(x) = log₂x

F(32) = log₂(32)

F(32) = log₂32^-1

F(32) = log₂(2⁵)^-1

F(32) = log₂2^{(5 x -1)}

F(32) = log₂2^-5

F(32) = -5log₂2

F(32) = -5 x 1

F(32) = -5

Therefore F(32) = -5

TRY THIS…………………

If F(x) = log₂x, Find F(512)