SETS 3

If n(A)= 65 , n(AuB) = 165 and n(AnB)=10, find n(B)

Solution

n(AuB) = n(A) + n(B) - n(AnB)

  165     = 65 + n(B)  – 10

  165     = 65 -10 + n(B) 

  165     = 55 + n(B) 

  165 - 55        = n(B)

  110        = n(B)

Hence n(B) = 110 answer

TRY THIS…………………………….

If n(A)= 64 , n(AuB) = 127 and n(AnB) = 33, find n(B).