Sunday 23 April 2017

LOGARITHMS 15


Evaluate Log2(1024 x 32).

Solution

= Log2(1024 x 32)

= Log21024 +  Log232          (applying the product rule)

= Log2210 +  Log225             (1024= 210 and 32=25 )

= 10Log22 +  5Log22       ( remember  Logaac = cLogaa )

= (10 x 1) +  (5 x 1)          ( remember  Logaa = 1 )

= 10 + 5

= 15

hence Log2(1024 x 32) = 15

TRY THIS………………



Evaluate Log2(256 x 64). 

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