The 1st term of an A.P. is 76 and
the common difference is 40. Find the 10th term.

__Solution__
A

_{1}= 76, d = 40
A

_{n}= A_{1}+ (n-1)d
A

_{10}= A_{1}+ (10-1)d
A

_{10}= A_{1}+ 9d
A

_{10}= 76 + (9x40) [ after substituting A_{1}= 76, d = 30 as given above]
∴ A

_{10}= 76 + 360
A

_{10}= 436

__Hence the 10th term is 436.__

__TRY THIS……………__
The 1st term of an A.P. is 60 and
the common difference is 48. Find the 7th term.

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