Wednesday 7 December 2016

LOGARITHMS 5


If log 2= 0.3010; find the value of log 125 without using tables.

solution

log125=log(1,000 ÷8)

=log1000 –log8

= log103 - log23

= 3log10 - 3log2

=(3 x 1) - (3 x 0.3010)

= 3  -  0.9030

=2.097

Hence log 125 =2.097

TRY THIS……………


If log 2= 0.3010; find the value of log 250 without using tables.

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