LOGARITHMS 13

If log 2= 0.3010; find the value of log 3,200,000 without using tables.

solution

log3,200,000=log(32 x 100,000)

=log32 + log100,000

=log2⁵ + log10⁵

=5log2 + 5log10

=5(0.3010) + (5 x 1)

=(1.5050) +  5

=6.5050

Hence log3,200,000=6.5050

TRY THIS……………

If log 2= 0.3010; find the value of log 160,000 without using tables.