SETS 8

If n(A)= 85 , n(B)= 96 and n(AuB)= 126, find n(AnB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

126 = 85 + 96 - n(AnB)

126 = 181 - n(AnB)

126 - 181 = - n(AnB)

-55 = -n(AnB)

n(AnB) = 55 [after dividing by -1 both sides]

Hence n(AnB) = 55 answer

TRY THIS………….

If n(A)= 93 , n(B)= 95 and n(AuB)= 124, find n(AnB).