SETS 6

If n(A)= 76 , n(B)= 90 and n(AuB)= 130, find n(AnB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

130 = 76 + 90 - n(AnB)

130 = 166 - n(AnB)

130 - 166 = - n(AnB)

-36 = -n(AnB)

n(AnB) = 36 [after dividing by -1 both sides]

Hence n(AnB) = 36 answer

TRY THIS………….

If n(A)= 74 , n(B)= 85 and n(AuB)= 120, find n(AnB).