Friday 5 February 2016

LOGARITHMS 2



Evaluate Log2(256 x 1/32).

Solution

= Log2(256  x 1/32).

= Log2256 +  Log2(1/32)          (applying the product rule)

= Log2256 +  Log232-1         ( since  1/32 = 32-1 )

= Log228 +  Log2(25) -1                      ( since 256= 28 and 32=25 )

= Log228 +  Log22-5   

= 8Log22 +  -5Log22       ( remember  Logaac = cLogaa )

= (8 x 1) +  (-5 x 1)          ( remember  Logaa = 1 )

= 8 + (-5)

= 3


Hence Log2(256 x 1/32) = 3

TRY THIS...............


Evaluate Log2(512 x 1/128).


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