Friday 19 February 2016

LOGARITHMS-10


If log5(3x + 101)=3; find x

   Solution

log5(3x + 92)=3

 (3x + 92)=53   
                      
 3x + 92=125

3x = 125 – 92

3x =  33

3x =  33   
3        3

X = 11

Hence x = 11

TRY THIS...............


If log2(2x - 22)=5; find x

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