MATHEMATICS PROBLEM SOLVER

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Thursday 4 February 2016

ARITHMETIC PROGRESSION 1

The 1st term of an A.P. is 70 and the common difference is 16. Find the 10th term.

Solution

A₁= 70, d = 20

A_n = A₁ + (n-1)d

A₁₀ = A₁ + (10-1)d

A₁₀ = A₁ + 9d

A₁₀ = 70 + (9x16) [ after substituting A₁= 70, d = 16 as given above]

∴ A₁₀ = 70 + 144

A₁₀ = 214

Hence the 10th term is 214.

TRY THIS……………

The 1st term of an A.P. is 30 and the common difference is 43. Find the 9th term.

MATHEMATICS PROBLEM SOLVER

Thursday 4 February 2016

ARITHMETIC PROGRESSION 1

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