Friday 11 December 2015

LOGARITHMS-9


If log5(3x + 101)=3; find x

   Solution

log5(3x + 101)=3

 (3x + 101)=53   
                      
 3x + 101=125


3x = 125 – 101

3x =  24


3x =  24   
3        3

X = 8


Hence x = 8

TRY THIS...............

If log2(2x - 14)=5; find x


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