Monday 14 December 2015

LOGARITHMS-8


Evaluate Log2(256 ÷ 8).

Solution

= Log2(256 ÷ 8)

= Log2256 -  Log28          (applying the quotient rule)

= Log228 -  Log223             ( 256= 28 and 8=23 )

= 8Log22 -  3Log22       ( remember  Logaac = cLogaa )

= (8 x 1) - (3 x 1)          ( remember  Logaa = 1 )

= 8 - 3

= 5


hence Log2(128 ÷ 8) = 5 

TRY THIS...............


Evaluate Log2(1024 ÷ 32). 

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