Saturday 28 November 2015

LOGARITHMS 1




Evaluate Log2(512 x 32).

Solution

= Log2(512 x 32)

= Log2512 +  Log232          (applying the product rule)

= Log229 +  Log225             ( 512= 29 and 32=25 )

= 9Log22 +  5Log22       ( remember  Logaac = cLogaa )

= (9 x 1) +  (5 x 1)          ( remember  Logaa = 1 )

= 9 + 5

= 14


hence Log2(512 x 32) = 14 

TRY THIS...............

Evaluate Log2(256 x 1024). 


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