Friday 11 September 2015

LOGARITHMS 1



Evaluate Log2(32 x 2).

Solution

= Log2(32 x 2)

= Log232 +  Log22          (applying the product rule)

= Log225 +  Log221             (32= 25 and 2=21 )

= 5Log22 +  1Log22       ( remember  Logaac = cLogaa )

= (5 x 1) +  (1x 1)          ( remember  Logaa = 1 )

= 5 + 1

= 6

hence Log2(32 x 2) = 6

TRY THIS………………


Evaluate Log2(128 x 4). 



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