A settlement has a
population of 2000 people. Each year 12%of the people leave the settlement. How
many people will remain after 3 years?

__solution__
f(t) = A ( 1 -12/100)

^{t}
= 2000(1 – 0.12)

^{t}
= 2000 x (0.88)

^{3}
= 2000 x 0.88x 0.88x 0.88

= 2000 x 0.681472

= 1362.944 (1363
approximate)

**Therefore there will be 1363 people remaining after three years of decay**

__TRY THIS………….__
A settlement has a
population of 5000 people. Each year 5%of the people leave the settlement. How
many people will remain after 4 years?