Wednesday 8 July 2015

SIMULTANEOUS EQUATIONS 1




Solve the following equations by substitution method.
x + y = 13
x + 3y = 27

Solution

x + y = 13 ----------- (i)
x + 3y = 27 ---------- (ii)

from equation (i)

x + y = 13
x = 13 - y ----------(iii)

substitute equation (iii) in (ii) above,

x + 3y = 27

(13 - y)  + 3y = 27

13 + 2y = 27            [since –y+3y=2y]

2y = 27 - 13

2y = 14
2      2

y = 7


From equation (iii)

x = 13 - y ----------(iii)
x = 13 - 7
x = 6


Hence x=6 and y=7.


TRY THIS………………………..

Solve the following equations by substitution method.
x + y = 10
2x + y = 13

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