Friday 1 May 2015

LOGARITHMS 1




Evaluate Log2(256 x 8).

Solution

= Log2(256 x 8)

= Log2256 +  Log28          (applying the product rule)

= Log228 +  Log223             ( 256= 28 and 8=23 )

= 8Log22 +  3Log22       ( remember  Logaac = cLogaa )

= (8 x 1) +  (3 x 1)          ( remember  Logaa = 1 )

= 8 + 3

= 11


hence Log2(128 x 8) = 11 

TRY THIS...............

Evaluate Log2(1024 x 32). 


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