POPULATION DECAY 1

A settlement has a population of 3000 people. Each year 5%of the people leave the settlement. How many people will remain after 3 years?

solution

f(t) = A ( 1 -5/100)^t

= 3000(1 – 0.05)^t

= 3000 x (0.95)³

= 3000 x 0.95 x 0.95 x 0.95

= 3000 x 0.857375

= 2572.125 (2572 approximate)

Therefore there will be 2572 people remaining after three years of decay

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A settlement has a population of 4000 people. Each year 7%of the people leave the settlement. How many people will remain after 4 years?