Thursday 30 April 2015

LOGARITHMS 20





Evaluate Log2(256 x 32).

Solution

= Log2(256 x 64)

= Log2256 +  Log264          (applying the product rule)

= Log228 +  Log226             ( 256= 28 and 32=25 )

= 8Log22 +  6Log22       ( remember  Logaac = cLogaa )

= (8 x 1) +  (6 x 1)          ( remember  Logaa = 1 )

= 8 + 6

= 14


hence Log2(256 x 64) = 14

TRY THIS...............

Evaluate Log2(512 x 128).


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