Saturday 25 April 2015

ARITHMETIC PROGRESSION 3




The 1st term of an A.P. is 70 and the common difference is 30. Find the 10th term.

Solution

A1= 70, d = 30

An = A1 + (n-1)d

A10 = A1 + (10-1)d

A10 = A1 + 9d

A10 = 70 + (9x30) [ after substituting A1= 70, d = 30 as given above]

A10 = 70 + 270

A10 = 340

Hence the 10th term is 340.



TRY THIS……………

The 1st term of an A.P. is 40 and the common difference is 33. Find the 7th term.

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