Monday 23 March 2015

WORD PROBLEMS 1


The sum of five consecutive numbers is 475. Find the 3rd number.

Solution

Let the numbers be as shown in the table below


1st number
2nd number
3rd number
4th number
5th
number
TOTAL
n
n+1
n+2
n+3
n+4
475


Then, n + (n+1) + (n+2) + (n+3)+ (n+4) = 475


5n + 1+2+3 +4= 475


5n + 10= 475


5n = 475 -10


5n = 465


5n = 465
5        5

n = 93


3rd number = n + 2
                  = 93 + 2
                  = 95



Hence the 3rd number is 95

TRY THIS..................


The sum of five consecutive numbers is 510. Find the 3rd number.


No comments:

Post a Comment