Monday 23 March 2015

ARITHMETIC PROGRESSION 1


The 1st term of an A.P. is 40 and the common difference is 58. Find the 12th term.

Solution

A1= 40, d = 58

An = A1 + (n-1)d   [ formula for n terms ]

A12 = A1 + (12-1)d

A12 = A1 + 11d    [ formula for 12 terms ]

A12 = 40 + (11 x 58)

A12 = 40 + 638

A12 = 678


Hence the 12th term is 678.

TRY THIS...................


The 1st term of an A.P. is 456 and the common difference is 70. Find the 12th term.

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