The 1st term of an A.P. is 40 and
the common difference is 58. Find the 12th term.

__Solution__

A

_{1}= 40, d = 58
A

_{n}= A_{1}+ (n-1)d [ formula for n terms ]
A

_{12}= A_{1}+ (12-1)d
A

_{12}= A_{1}+ 11d [ formula for 12 terms ]
A

_{12}= 40 + (11 x 58)
A

_{12}= 40 + 638
A

_{12}= 678

__Hence the 12th term is 678.__

__TRY THIS...................__
The 1st term of an A.P. is 456 and
the common difference is 70. Find the 12th term.