LOGARITHMS 1

Evaluate Log₂(4 x 256).

Solution

= Log₂(4 x 256)

= Log₂4 +  Log₂256          (applying the product rule)

= Log₂2² +  Log₂2⁸             ( 4= 2² and 256=2⁸ )

= 2Log₂2 +  8Log₂2       ( remember  Log_aa^c = cLog_aa )

= (2 x 1) +  (8 x 1)          ( remember  Log_aa = 1 )

= 2 + 8

= 10

hence Log₂(4 x 256) = 10

TRY THIS……………..

Evaluate Log₂(4 x 16).