Saturday 17 January 2015

FUNCTIONS 1




If F(x) = log3x,   Find F(59049)

Solution

F(x) = log3x

F(59049)= log3(59049)

F(59049)= log3310  [59049= 3x3x3X3X3X3X3X3X3X3=310 by prime factorization]



F(59049)= 10log33

F(59049)= 10x 1

F(59049) = 10

Therefore F(59049) = 10

TRY THIS……………………….

If F(x) = log3x, Find F(1287)

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