Wednesday 31 December 2014

LOGARITHMS 3


Evaluate Log2(1024 x 16).

Solution

= Log2(1024 x 16)

= Log21024 +  Log216          (applying the product rule)

= Log2210 +  Log224             (1024= 210 and 16=24 )

= 10Log22 +  4Log22       ( remember  Logaac = cLogaa )

= (10 x 1) +  (4 x 1)          ( remember  Logaa = 1 )

= 10 + 4

= 14

hence Log2(1024 x 16) = 14

TRY THIS………………


Evaluate Log2(32 x 64). 

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