LOGARITHMS 1

Evaluate Log₂(128 x 16).

Solution

= Log₂(128 x 16)

= Log₂128 +  Log₂16          (applying the product rule)

= Log₂2⁷ +  Log₂2⁴             (32= 2⁵ and 16=2⁴ )

= 7Log₂2 +  4Log₂2       ( remember  Log_aa^c = cLog_aa )

= (7 x 1) +  (4 x 1)          ( remember  Log_aa = 1 )

= 7 + 4

= 11

hence Log₂(128 x 16) = 11

TRY THIS………………

Evaluate Log₂(256 x 4).