Tuesday 7 October 2014

LOGARITHMS 9


Evaluate Log2(32 x 16).

Solution

= Log2(32 x 16)

= Log232 +  Log216          (applying the product rule)

= Log225 +  Log224             ( 32= 25 and 16=24 )

= 5Log22 +  4Log22       ( remember  Logaac = cLogaa )

= (5 x 1) +  (4 x 1)          ( remember  Logaa = 1 )

= 5 + 4

= 11

hence Log2(32 x 16) = 11

TRY THIS…………………

Evaluate Log2(8 x 32).


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