Thursday 6 March 2014

LOGARITHMS C2


If logx625 + log381 = 7; find x

Solution

logx625 + log381 = 7

logx625 + log334 = 7  [81=33 by prime factorization]

logx625 + 4log33 = 7  [since logaa= nlogaa]

logx625 + (4 x 1) = 7  [logaa = 1]

logx625 + 4 = 8

logx625 = 8- 4

logx625 = 4

625 = x4

54 = x4      Powers cancel out

x = 5


Hence x = 5.

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