Thursday 13 March 2014

ARITHMETIC PROGRESSION C2



Find the sum of the 1st 30 terms of the following arithmetic progression: 4+6+8+…………………

Solution

d=2, A1 = 4,n=30

Sn = n[2A1 + (n-1)d]
      2

S30 = 30[2(4) + (30-1)d]
        2

S30 = 15[8 + 15d]
 
S30 = 15[8 + 13(2)]       since d=2

S30 = 15[8 + 26]     
    
S30 = 15 x 34      
     
S30 = 510

Therefore the sum of 1st 16 terms is 510.

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